From 2c1b1a48d3b4c0fb7a9f2bcea668eb4e5079c2d2 Mon Sep 17 00:00:00 2001
From: HombreLaser <sebastian-440@live.com>
Date: Thu, 11 Jan 2024 12:17:36 -0600
Subject: Añade más problemas y linebreaks
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---
 main.tex | 128 ++++++++++++++++++++++++++-------------------------------------
 1 file changed, 53 insertions(+), 75 deletions(-)

(limited to 'main.tex')

diff --git a/main.tex b/main.tex
index b42f579..a3f4e70 100644
--- a/main.tex
+++ b/main.tex
@@ -2,86 +2,64 @@
 \usepackage{graphicx} % Required for inserting images
 
 \title{Laboratorio}
-\author{Alexx}
+\author{
+  Alejandro Beltrán Alvarado
+  \and
+  Andrea Montserrat
+  \and
+  Juan Carlos Diaz Gonzalez
+  \and
+  Luis Sebastián Martínez Vega
+}
 \date{January 2024}
 
 \begin{document}
 
 \maketitle
 
-\textbf{Encuentre el término de orden $r=4$ $(x+4)^4$}
+\begin{itemize}
+\item \textbf{Encuentre el término de orden $r=4$ $(x+4)^4$}
+  \\
+  \\
+  \\
+  \\
+  \\
+  
+\item \textbf{Desarrolle $n=4 (3x+5)^4$}
+  \\
+  \\
+  \\
+  \\
+  \\
+
+\item \textbf{Desarrolle $ (y+5x)^4$}
+  \\
+  \\
+  \\
+  \\
+  \\
+
+\item \textbf{Desarrolle $(2x+3y)^5$}
+  \\
+  \\
+  \\
+  \\
+  \\
+
+\item \textbf{Del binomio $(64a^2+8b)^8$, obtener el sexto termino.}
+  \\
+  \\
+  \\
+  \\
+  \\
+
+\item \textbf{Del binomio $(32x^3+x^2y)^{10}$), obtener el término que contenga  $x^8y^4$}
+  \\
+  \\
+  \\
+  \\
+  \\
+
+\end{itemize}
 
-\[
-\frac{n(n-1)\ldots(n-r+2)}{(r-1)!}a^{n-r+1}b^{r-1}
-\]
-
-\[
-= \frac{4(4-1)(4-2)}{(4-1)!}x^{4-4+1}(4^{4-1})
-\]
-
-\[
-= \frac{4(3)(2)}{(3)!}x^{4-4+1}(4^{4-1})
-\]
-
-\[
-= \frac{24}{(3)!}x^{4-4+1}(4^{4-1})
-\]
-
-\[
-= \frac{24}{6}x^{4-4+1}(4^{4-1})
-\]
-
-\[
-= 4x^{4-4+1}(4^{4-1}) = (4x^{1})(4^{3}) = 256x
-\]
-
-\textbf{Desarrolle $(3x+5)^4$}
-
-\[
-(3x+5)^4
-\]
-
-\[
-= 81x^4+4(3x)^{4-1}(5)+\frac{4(4-1)}{2!}(3x)^{4-2}(5^2)+\frac{4(4-1)(4-2)}{3!}(3x)^{4-3}(5^3)+5^4
-\]
-
-\[
-= 81x^4+4(27x)^{3}(5)+\frac{4(4-1)}{2!}(3x)^{4-2}(5^2)+\frac{4(4-1)(4-2)}{3!}(3x)^{4-3}(5^3)+5^4
-\]
-
-\[
-= 81x^4+540x^3+\frac{4(3)}{2}(3x)^{4-2}(5^2)+\frac{4(4-1)(4-2)}{3!}(3x)^{4-3}(5^3)+5^4
-\]
-
-\[
-= 81x^4+540x^3+(6)(9x^2)(5^2)+\frac{4(4-1)(4-2)}{3!}(3x)^{4-3}(5^3)+5^4
-\]
-
-\[
-= 81x^4+540x^3+1,350x^2+\frac{4(3)(2)}{6}(3x)^{4-3}(5^3)+5^4
-\]
-
-\[
-= 81x^4+540x^3+1,350x^2+(4)(3x)^{4-3}(9)+5^4
-\]
-
-\[
-= 81x^4+540x^3+1,350x^2+(12x)(5^3)+5^4
-\]
-
-\[
-= 81x^4+540x^3+1,350x^2+(12x)(125)+5^4
-\]
-
-\[
-= 81x^4+540x^3+1,350x^2+1500x+5^4
-\]
-
-\[
-= 81x^4+540x^3+1,350x^2+1500x+625
-\]
-
-\textbf{Desarrolle $(y+5x)^4$}
-
-\textbf{Desarrolle $(2x+3y)^5$}
 \end{document}
-- 
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